handle cases where datasourceName is undefined when sorting datasources

2024-12-09 10:29:37 +00:00 · 2024-12-09 10:29:37 +00:00 · 997daf17d0
parent e790a04228
commit 997daf17d0
1 changed files with 4 additions and 1 deletions
--- a/packages/builder/src/components/design/settings/controls/DataSourceSelect/DataSourceSelect.svelte
+++ b/packages/builder/src/components/design/settings/controls/DataSourceSelect/DataSourceSelect.svelte
@ -56,7 +56,10 @@
    .map(table => format.table(table, $datasources.list))
    .sort((a, b) => {
      // sort tables alphabetically, grouped by datasource
-      const dsComparison = a.datasourceName.localeCompare(b.datasourceName)
+      const dsA = a.datasourceName ?? ""
+      const dsB = b.datasourceName ?? ""
+
+      const dsComparison = dsA.localeCompare(dsB)
      if (dsComparison !== 0) {
        return dsComparison
      }