87 lines
2.9 KiB
Python
87 lines
2.9 KiB
Python
#!/usr/bin/env python3
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# Copyright (C) 2013-2016 Florian Festi
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#
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# This program is free software: you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation, either version 3 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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from boxes import *
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class JigsawPuzzle(Boxes): # change class name here and below
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"""Fractal jigsaw puzzle. Still aplha"""
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webinterface = False # Change to make visible in web interface
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def __init__(self):
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Boxes.__init__(self)
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self.count = 0
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self.argparser.add_argument(
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"--size", action="store", type=float, default=100,
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help="size of the puzzle in mm")
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self.argparser.add_argument(
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"--depth", action="store", type=int, default=5,
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help="depth of the recursion/level of detail")
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def peano(self, level):
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if level == 0:
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self.edge(self.size / self.depth)
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return
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self.peano(self, level - 1)
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self.corner()
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def edge(self, l):
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self.count += 1
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Boxes.edge(self, l)
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# if (self.count % 2**5) == 0: #level == 3 and parity>0:
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# self.corner(-360, 0.25*self.size/2**self.depth)
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def hilbert(self, level, parity=1):
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if level == 0:
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return
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# rotate and draw first subcurve with opposite parity to big curve
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self.corner(parity * 90)
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self.hilbert(level - 1, -parity)
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# interface to and draw second subcurve with same parity as big curve
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self.edge(self.size / 2 ** self.depth)
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self.corner(parity * -90)
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self.hilbert(level - 1, parity)
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# third subcurve
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self.edge(self.size / 2 ** self.depth)
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self.hilbert(level - 1, parity)
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# if level == 3: self.corner(-360, 0.4*self.size/2**self.depth)
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# fourth subcurve
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self.corner(parity * -90)
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self.edge(self.size / 2 ** self.depth)
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self.hilbert(level - 1, -parity)
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# a final turn is needed to make the turtle
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# end up facing outward from the large square
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self.corner(parity * 90)
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# if level == 3 and parity>0: # and random.random() < 100*0.5**(self.depth-2):
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# self.corner(-360, 0.4*self.size/2**self.depth)
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# with self.savedcontext():
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# self.corner(parity*-90)
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# self.edge(self.size/2**self.depth)
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def render(self):
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size = self.size
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t = self.thickness
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self.burn = 0.0
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self.moveTo(10, 10)
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self.hilbert(self.depth)
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